If the characteristic frequency of a material is 125 Hz, what test frequency is required for an f/f ratio of 10?

To find the test frequency required for an f/f ratio of 10 when the characteristic frequency is 125 Hz, you multiply the characteristic frequency by the f/f ratio.

The f/f ratio can be understood as a dimensionless number that represents the relationship between the test frequency (f) and the characteristic frequency (f_c). In this case, the formula to compute the test frequency is:

[ f = f_c \times \text{f/f ratio} ]

Given that the characteristic frequency (f_c) is 125 Hz and the f/f ratio is 10, the calculation is as follows:

[ f = 125 \text{ Hz} \times 10 = 1250 \text{ Hz} ]

Since 1 kHz is equal to 1000 Hz, 1250 Hz can be expressed as 1.25 kHz. Therefore, the correct test frequency is 1.25 kHz.

This aligns with the correct choice provided, confirming that the calculated test frequency adheres to the requirements of the f/f ratio in relation to the characteristic frequency.